| T.R | Title | User | Personal Name
 | Date | Lines | 
|---|
| 2060.1 | complex numbers? | FLOYD::YODER | MFY | Fri Aug 30 1996 16:29 | 14 | 
|  | I think that "all" you get are complex numbers.  That is, if
  x = arcsinh(2)
then
  ix = arcsin(2)
is "merely" an imaginary number.
So your second example is arguably the same as the first!
                    ix   -ix
In C,    sin(x) = (e  - e   )/2i.
 | 
| 2060.2 |  | RUSURE::EDP | Always mount a scratch monkey. | Tue Sep 03 1996 08:42 | 11 | 
|  |     In Derive (or most symbolic math packages), enter asin(2) and simplify
    to get:
    
    	pi/2 - i ln(sqrt(3)+2).
    
    
    				-- edp
    
    
Public key fingerprint:  8e ad 63 61 ba 0c 26 86  32 0a 7d 28 db e7 6f 75
To find PGP, read note 2688.4 in Humane::IBMPC_Shareware.
 | 
| 2060.3 | if sin(a) = 2 then ... | PAWN21::OSMAN | see HANNAH::IGLOO$:[OSMAN]ERIC.VT240 | Tue Sep 03 1996 09:51 | 16 | 
|  | 
sin(a) = 2
sin^2 + cos^2  = 1
so
2^2+cos^2 = 1
cos^2 = -3
cos(a) = sqrt(-3)
Does this help ?
/Eric
 | 
| 2060.4 | re: .3 | BEGIN::YODER | MFY | Tue Sep 03 1996 10:18 | 9 | 
|  |     >Does this help?
    
    It helps in that it suggests that the arcsin(2) extension might be
    related to the sqrt(-1) extension (and we know that it is).
    
    You have hit upon a problem that happens to be solved, though I
    wouldn't mind if this turned into a discussion of functions over
    the complex plane (especially if it became a discussion of
    algorithms).
 |