| Title: | Mathematics at DEC |
| Moderator: | RUSURE::EDP |
| Created: | Mon Feb 03 1986 |
| Last Modified: | Fri Jun 06 1997 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 2083 |
| Total number of notes: | 14613 |
Need some help to solve this problem:
a = 180(n - 2)
----------
n
Solve for n
Please show details!
Thanks,
Jack
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 1826.1 | STAR::ABBASI | sleeples days.... | Mon Dec 20 1993 13:18 | 18 | |
>a = 180(n - 2)
> ----------
> n
multiply both sides by n =>
a n = 180(n-2)
a n = 180 n - 360
move terms with n to one side, and known terms to the other side
a n - 180 n = -360
n(a-180) = -360
- 360 360
n= --------- = ----------
a-180 180 - a
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| 1826.2 | WRKSYS::ARUMUGHAM | Tue Dec 21 1993 17:05 | 3 | ||
Re .0
This is something for total angles (something like that) in an n sided
polygon, right?
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| 1826.3 | AUSSIE::GARSON | Hotel Garson: No Vacancies | Tue Dec 21 1993 20:42 | 3 | |
re .-1
An angle in a regular n-gon. e.g. n = 3 gives a = 60, n = 4 gives a = 90
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