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| Title: | Mathematics at DEC | 
|  | 
| Moderator: | RUSURE::EDP | 
|  | 
| Created: | Mon Feb 03 1986 | 
| Last Modified: | Fri Jun 06 1997 | 
| Last Successful Update: | Fri Jun 06 1997 | 
| Number of topics: | 2083 | 
| Total number of notes: | 14613 | 
359.0. "A maximal triangle" by TOOLS::STAN () Fri Oct 18 1985 21:52
Just so that we don't start a precedent of only posing hard problems
in this note file, let me throw out an easy one (you "heavies" please
refrain from answering this too fast - give newcomers a chance):
The triangle with sides 25-25-30 has the same area as the triangle
with sides 25-25-40.  At first this sounds anomalous, but a little
thought will show why this is true.
Anyhow, it means that as you take a pair of dividers with sides of
length 25 and open them up, the area formed starting at 0 gets larger,
passes through 25-25-30 (where the area is 300), hits some maximum,
starts to get smaller, passes through 25-25-40 (with area 300 again),
and ends up at 25-25-50 with area 0 again.  Thus we see that there is
some value x for which the triangle with sides 25, 25, x has maximum
area.  What is this value of x?
| T.R | Title | User | Personal Name
 | Date | Lines | 
|---|
| 359.1 |  | TOOLS::STAN |  | Wed Nov 20 1985 19:22 | 1 | 
|  | This problem is now open to all takers.
 | 
| 359.2 |  | R2ME2::GILBERT |  | Wed Nov 20 1985 21:36 | 1 | 
|  | 25 sqrt(2), or roughly 35.3553.
 |