| Title: | Mathematics at DEC | 
| Moderator: | RUSURE::EDP | 
| Created: | Mon Feb 03 1986 | 
| Last Modified: | Fri Jun 06 1997 | 
| Last Successful Update: | Fri Jun 06 1997 | 
| Number of topics: | 2083 | 
| Total number of notes: | 14613 | 
Find a right triangle with rational sides and area 5. Reference --------- H.G. Zimmer, Congruent Numbers - From Elementary to Algebraic Number Theory. SIGSAM Bulletin. 18(1984)54-62.
| T.R | Title | User | Personal Name | Date | Lines | 
|---|---|---|---|---|---|
| 278.1 | RAINBO::GRANT | Tue May 07 1985 10:53 | 8 | ||
| My little computer here tells me that sides of 3/2 and 20/3 give an area of 5 and a hypotenuse of 41/6. Scanning the output, there seem to be no more answers where the fractions are reduced to simplest terms, and all the numerators and denominators are less than 100. ( I was expecting some obscure answer with multi-digit denominators.) -Jim Grant, Littleton | |||||